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1
A reaction is second order in A and first order in B.
Differential rate equation:-
 (ii) On increasing the concentration of A three times i.e. 3A:
Rate = k[3A
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1
Let (x, y) be the point on  which is nearest to the point (–1, 2).                                                   At  
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1
(i) We have,
x + y = 5    ...(i)
⇒    y = 5 - x
Thus, we have following table2x + 2y = 10                      ...(ii)Thus, we have followin
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1
The strategies for sustainable development are:
(i) Use of Non- Conventional Sources of Energy: India is hugely dependent on thermal and hydropower plants to meet its power needs. Both of these have adverse environmental impacts. Thermal powerplants emit large quantities of carbon dioxide which is a green -house gas. Hydroelectric projects inundate forests and interfere with the natural flow of water in catchment areas and the river basins. Wind power and solar rays are examples of conventional but cleaner and greener technologies which can be effectively used to replace thermal and hydro-po
1
A bullets-board had been put up at the Town Hall two years ago for every news and the announcement. All their bad news came from German occupations. The detail
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1
Given,Capacitance of the capacitor, C= 0.1 FPotential applied across the capactor, V = 10 VTherefore,Energy stored in the first capacitor is
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1
Given: Triangle ABC and ∆PQR in which AD and PM are medians drawn on sides BC and QR respectively. It is given that
AB over PQ equals AC over PR equals AD over PM
To Prove : ∆ABC ~ ∆PQR
Const : Produce AD to E such that AD = DE and PM to F such that PM = MF.

Given: Triangle ABC and ∆PQR in which AD and PM are medians drawn o

Proof : In ∆ABD and ∆CDE,
AD = DE [by construction]
∠ADB = ∠CDE
[vertically opposite angles]
and BD = DC [AD is a median]
Therefore, by using SAS congruent condition
1
The conductivity (k) of the solution in a cell is the reciprocal of its resistivity.
 
The quantity  1/2  is cell constant.
L --> Distance between 2 ele
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1
यहाँ पर,
पेटी में डिस्कों पर अंकित संख्याएँ = 90 (1 से 90 तक)
rightwards double arrow सभी संभव परिणामों की संख्या = 90
(i) दो अंकों की संख्याओं वाली डिस्क की संख्या = 81 (10 से 90 तक)
rightwards double arrow अनुकूल परिणामों की संख्या = 81
∴ P(दो अंकों की एक संख्या वाली डिस्क ) = 81 over 90 equals 9 over 10
(ii) एक पूर्ण वर्ग संख्या वाली डिस्कों की संख्या = 9(1, 4, 9, 16, 25, 36, 49, 64, 81)
rightwards double arrow अनुकूल परिणामों की संख्या = 9
∴ P(एक पूर्ण वर्ग संख्या वाली डिस्क) = 9 over 90 equals 1 over 10
(iii) 5 से विभाज्य संख्या वाली डिस
1
Electronic configuration of Cr is 4s1 3d5. In the complex  [Cr(NH3)6]3+  Cr is in the +3 oxidation state i.e., d3 configuration. Also, NH3 is a w
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